Power Generation/Diesel Power/Part4

If heat produced by _X kg of oil = Y KCal (where 1kWh = 860 KCal)

Then we can derive the overal power plant efficiency as:

${\eta }_{overall}=\frac{860KCal}{YKCal}\times 100$ (in %) ... Equation 4.1

Then the engine efficiency becomes:

${\eta }_{engine}=\frac{{\eta }_{o}verall}{{\eta }_{a}lternator}\times 100$(in %) ... Equation 4.2

Where:_ ${\eta }_{alternator}$ is specified by manufacturer