Mesoscopic Physics/Mesoscopic Physics Glossary/Boltzmann Distribution: Difference between revisions

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imported>Dave Braunschweig
 
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Latest revision as of 04:01, 31 December 2020

Given a quantum system with energy eigenvalues En, in equilibrium the probability of finding the system in state n is given by the Boltzmann distribution,

pn=1Zexp(EnkBT),

where Z is the partition sum that makes the distribution normalized.

In terms of the system's density matrix, this is equivalent to saying

ρ^=1Zexp(H^kBT),

where H^ is the system's Hamiltonian.

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