Physics equations/22-Magnetism/Q:AmpereLawCALC

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pe22AmpereLawCalc A

<quiz display=simple> {H is defined by, B=μ₀H, where B is magnetic field. A current of 48A passes along the z-axis. Use symmetry to find the integral, $\int \overrightarrow{H}\cdot \overrightarrow{d\ell }$, from the point Template:Nowrap begin(0,6.7)Template:Nowrap end to the point Template:Nowrap begin(6.7,0)Template:Nowrap end.} -a) 9.10E+00 amps -b) 9.98E+00 amps -c) 1.09E+01 amps +d) 1.20E+01 amps -e) 1.32E+01 amps

{H is defined by, B=μ₀H, where B is magnetic field. A current of 67A passes along the z-axis. Use symmetry to find the integral, $\int \overrightarrow{H}\cdot \overrightarrow{d\ell }$, from the point Template:Nowrap begin(-6.1, 6.1)Template:Nowrap end to the point Template:Nowrap begin(6.1, 6.1)Template:Nowrap end.} -a) 1.27E+01 amps -b) 1.39E+01 amps -c) 1.53E+01 amps +d) 1.68E+01 amps -e) 1.84E+01 amps

{H is defined by, B=μ₀H, where B is magnetic field. A current of 84A passes along the z-axis. Use symmetry to find the integral, $\int \overrightarrow{H}\cdot \overrightarrow{d\ell }$, from the point Template:Nowrap begin(0,9.3)Template:Nowrap end to the point Template:Nowrap begin(9.3,9.3)Template:Nowrap end.} +a) 1.05E+01 amps -b) 1.15E+01 amps -c) 1.26E+01 amps -d) 1.38E+01 amps -e) 1.52E+01 amps

{H is defined by, B=μ₀H, where B is magnetic field. A current of 81A passes along the z-axis. Use symmetry to find the integral, $\int \overrightarrow{H}\cdot \overrightarrow{d\ell }$, from Template:Nowrap begin(-∞,6.4)Template:Nowrap end to Template:Nowrap begin(+∞,6.4)Template:Nowrap end.} -a) 3.37E+01 amps -b) 3.69E+01 amps +c) 4.05E+01 amps -d) 4.44E+01 amps -e) 4.87E+01 amps

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