Complex Analysis/Exercises/Paper 1

From testwiki
Jump to navigation Jump to search

Problem Set 1 - Complex Analysis

Problem 1 (Field Structure of the Complex Numbers)

We define :=2={(ab);a,b} the following links and . Definition:for (ab),(cd):
(ab)(cd):=(a+cb+d) und (ab)(cd):=(acbdad+bc)

  1. Show that (,,) is a field, i.e.:

    1. is commutative and associative and has a neutral element 0. Additionally, every element of is invertible with respect to .

    2. is commutative and associative and has a neutral element 1. Additionally, every element of {0} is invertible with respect to .

    3. For and distributive law holds.

    Your proof should identify,0 and 1 are and what to (ab) Inverse with respect to or. (in case (ab)0) the Inverse with respect to is.

  2. show that ,the figure ϕ:,ϕ(a)=(a0) is an injective field homomorphism. This means ϕis injective and satisfies:
    ϕ(a+b)=ϕ(a)+ϕ(b) and ϕ(ab)=ϕ(a)ϕ(b)for all a,b

Problem 2 (Arithmetic in the Complex Field)

We now use + und for the operations und auf defined in Problem 1.Additionally, fora we simply write a instead of ϕ(a)=(a0).In this notation, .)Let i:=(01).

  1. Show that for all a,b: a+ib=(ab).
  2. Show that i2=1.
  3. Compute: x for the follwing equatios:
    1. x2=1.
    2. x2=1.
    3. x4=1.

Problem 3 (Real and Imaginary Parts, Complex Conjugates, and Moduli)

Prove the following:

  1. For all x,y, Re(x+y)=Re(x)+Re(y) and Im(x+y)=Im(x)+Im(y).
  2. For all x, Re(x)=x+x¯2 and Im(x)=xx¯2i.
  3. For all x, xx¯=|x|2 and (if x0) 1x=x¯|x|2.
  4. For all x,y, |xy|=|x||y| and (if y0) |xy|=|x||y|.
  5. For all x,y, |x+y||x|+|y|.

Translation and Version Control

This page was translated based on the following Wikiversity source page and uses the concept of Translation and Version Control for a transparent language fork in a Wikiversity:

https://de.wikiversity.org/wiki/Kurs:Funktionentheorie/Übungen/1._Blatt

  • Date: 01/14/2024


de:Kurs:Funktionentheorie/Übungen/1._Blatt