Fluid Mechanics for Mechanical Engineers/Energy Considerations in Internal Flows

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Losses and Energy consideration

Remember the conservation of energy equation:

Template:Center topQ˙+W˙shaft+W˙shear+W˙other=tCVeρdV+CS(e+Pρ)ρUinidATemplate:Center bottom


where

Template:Center tope=u+U22+gx2=u+UiUi2+gzTemplate:Center bottom

The velocity does not have necessarily a plug profile at the inlet and outlet of a control volume and the cross sectional areas might also differ at the inlet and outlet of a CV. The variations in the cross sections of flow conduits and the velocity profiles have to be accounted to calculate the correct pressure drop due to the viscous losses. Therefore, the surface integrals has to be calculated by considering these variations:

Template:Center topQ˙=CS(e+Pρ)ρUinidA=m˙(u2u1)+m˙(P2ρP1ρ)+m˙g(z2z1)+Template:Center bottom


Template:Center topA2U222ρU2in2idAA2U122ρU1in1idATemplate:Center bottom

For the calculation of the profile effects one can use the kinetic energy coefficient α as follows:

Template:Center topAU22ρUinidA=αm˙U¯22Template:Center bottom


For fully developed laminar velocity profile, where


Template:Center topU=2U¯[1rR2]Template:Center bottom

α=2


For fully developed turbulent flow, due to relatively flat velocity profile, α1

File:Losses energy.png
Velocity profiles for laminar (upper) and turbulent (lower) states at the same mass flow rate


Template:Center topQ˙=m˙(u2u1)+m˙(P2ρP1ρ)+m˙(α2U¯222α1U¯122)Template:Center bottom


Rearranging the energy equation:


Template:Center topP1ρ+α1U¯122+gz1=P2ρ+α2U¯222+gz2A+(u2u1)Q˙m˙BTemplate:Center bottom

The conversion of mechanical energy (A) and the irreversible conversion and loss of mechanical energy with viscous dissipation (B) can be better distinguished.

Total pressure drop

Finally the total pressure drop due to viscous effects can be written as

Template:Center topP1+α1ρU¯122+ρgz1=P2+α2ρU¯222+ρgz2Mechanical Energy+ΔPvPressure drop due to viscous lossesTemplate:Center bottom


Template:Center topΔPv=(P1P2)+ρ(α1U¯122α2U¯222)+ρg(z1z2)Template:Center bottom

Major and minor pressure losses

l

The total pressure drop consist of major losses, which are due to frictional effects in fully developed flow in constant area tubes, and minor losses, which occur at entrances, sudden area changes, bends, elbows, fittings, valves, contraction and diffusers, etc..


Major losses in pipe flows

Moody diagram


The pressure drop along a pipe, which has no elevation change, can be written as:


Template:Center topΔPv=(P1P2)Template:Center bottom


Nondimensionalizing with the kinetic energy per unit mass of the flow:


Template:Center topζ=ΔPv0.5ρU¯2=LD f(Re,eD)Template:Center bottom


where ζ is the loss coefficient and f is the friction factor.


Non-circular ducts

For non circular ducts, which appears in air conditioning, heating and ventilating applications, an equivalent diameter is calculated so that correlations for circular pipes can be utilized.

This equivalent diameter is called as hydraulic diameter:


Template:Center topDh=4×AreaPerimeter=4APTemplate:Center bottom


Thus for a rectangular duct with a width of b and height of h:


Template:Center topDh=4bh2(b+h)Template:Center bottom


And for a square duct

Template:Center topDh=hTemplate:Center bottom


Minor losses

For the other components which might cause pressure drop, the loss coefficient (resistance coefficient) can similarly be defined:


Template:Center topζ=ΔPv0.5ρU¯2Template:Center bottom


However, for the vast variety of geometries, it is not possible to obtain relations as for the pipe flows. Thus, ζ for each component is measured and documented.


Fittings
Valve

Loss coefficient of standard components

File:Elbow 1.png
Elbow geometry
File:Loss energy in valves.svg
Range of loss coefficients for different valves and flaps
File:Resistance Coefficient 2.png
Range of loss coefficients for circular bellmouth inlet(collector)
File:Losses energie 8.png
The loss coeffecicent data for various elbow dimensions
File:Resistance Coefficient 1.png
Range of loss coefficients for the entrance into a straight tube of constant cross section
File:Resistance Coefficient 3.png
Range of loss coefficients for sudden expansion of a flow having a uniform velocity distribution

Calculation of total loss in a single pipe system

A single pipe system may have many minor losses. Since all are correlated with 0.5ρU¯2, they can be summed into a single total system loss if the pipe has constant diameter:


Template:Center topΔPtotal=ΔPpipe+ΔPcomponents=Template:Center bottom


Template:Center top0.5ρU¯2[LDf+iζi]Template:Center bottom


However, we must sum the losses separately, if the pipe size changes, i.e. mean velocity changes.

Multiple path system

File:Losses energie11 2.png

The solution for pipe network problems is often carried out by use of node and loop equations similar in many ways to that done in electrical circuits.

  1. The net flow into any junction must be zero.
  2. The net head loss around any closed loop must be zero. At each junction there is one single pressure.
  3. All head losses must satisfy the major and minor-loss friction correlations.


In such problems the pipes and components might have different areas, thus pressure loss at each pipe and component should be calculated separately. Moreover, there can be components with unknown properties.

For such cases it is found useful to formulate the pressure loss as a function of the flow rate:


Template:Center topΔP=ζ0.5ρU¯2=ζ0.5ρA2KQ2=KQ2Template:Center bottom


Resultant loss coefficients, Kr, for serial and parallel connections

Serial connection: Flow rate is the same for all components

File:Losses energie12.png

Template:Center topKr=K1+K2Template:Center bottom


Template:Center topΔPr=KrQ2=ΔP1+ΔP2=(K1+K2)Q2Template:Center bottom


Parallel connection: Pressure drop is the same inlet and outlet junctions

File:Losses energie13.png

Template:Center topKr=K1K2K1+K2+2K1K2Template:Center bottom


Template:Center topΔPr=KrQtotal2=K1Q12=K2Q22Template:Center bottom


Template:Center topQtotal=Q1+Q2Template:Center bottom

Design of a dry powder inhaler

The utilization of the explained concepts will be demonstrated in the class by explaining the design method of a dry powder inhaler. The basic steps of the design are as follows:

File:Designpablo.png
Schematics for Inhaler flow
  1. Make a conceptual design
  2. Decide pressure drop-flow rate characteristic of the inhaler (Inhaler patient matching)
  3. Dimension each component of the inhaler to ensure
    • Pressure drop-flow rate characteristic
    • Full emptying of the blister
    • Sufficient dispersion of the powder composition

An overview of dry powder inhaler design could be found in in the following publication [1]

Reference

Template:Reflist

Template:CourseCat

  1. Int J Pharm. 2011 Sep 15;416(1):25-34. doi: 10.1016/j.ijpharm.2011.05.045. Epub 2011 Jun 28. A method for the aerodynamic design of dry powder inhalers. Ertunç O, Köksoy C, Wachtel H, Delgado A.