Magnetic Gravity

Template:Research project this wikiversity original research on

how gravity and inertia emerge from electromagnetic formulae

and

how they might be large-number electromagnetic interactions

has just started and you are about to read sketch notes unripe for print until this very warning is altered because the argument became more elaborated:

Sanchez Exponential

In his horribly typeset but brilliantly

helpful paper

http://vixra.org/pdf/1609.0217v3.pdf

Calculation of the gravitational constant G using electromagnetic parameters

2016-09-14 ©©-by jesus.sanchez.bilbao@gmail.com

peer reviewed, printed, and republished in

http://file.scirp.org/pdf/JHEPGC_2016122915423655.pdf

Journal of High Energy Physics, Gravitation and Cosmology, 2017, 3, 87-95

independent researcher Jesús Sánchez discovered

the equation

$\frac{{\alpha }_g}{(2\pi \alpha {)}^2}=\frac{G{m}_e^2}{2\pi {\alpha }^{2}ch}=\frac{G{m}_e^2{ϵ}_0}{\alpha \pi q_e^2}=\frac{G{m}_e^{2}ch}{\frac{\pi }{2}{q}_e^4{ϵ}_0^{-2}}$

$=\frac{Gh}{8{\pi }^3{c}^3{r}_e^2}=\frac{Gh}{(2\pi c{)}^3{r}_e^2}=\frac{r_s{r}_c}{(4\pi r_e{)}^2}=\frac{{\ell }_P^2}{2\pi r_e^2}$

$=\exp (\frac{\sqrt{2}\alpha \pi }{4}-\frac{1}{\sqrt{2}\alpha })={\sqrt[-\sqrt{2}]{e}}^{\frac{1}{\alpha }-\frac{\alpha \pi }{2}}=e^{-96.891}$

$=2^{-139.784}=10^{-42.079}=\mathtt{\text{8.33E-43}}$

using $\exp (\ln (x))=x$

on $\exp (\ln (\frac{r_s{r}_c}{(4\pi r_e{)}^2}))=\exp (\frac{\sqrt{2}\alpha \pi }{4}-\frac{1}{\sqrt{2}\alpha })$

using $\exp (x)=\exp (x)$

on $\ln (\frac{r_s{r}_c}{(4\pi r_e{)}^2})=\frac{\sqrt{2}\alpha \pi }{4}-\frac{1}{\sqrt{2}\alpha }$

using $x=0+x$

on $0=\frac{\sqrt{2}\alpha \pi }{4}-\ln (\frac{r_s{r}_c}{(4\pi r_e{)}^2})-\frac{1}{\sqrt{2}\alpha }$

using $\alpha =r_e/r_c$

on $0=\frac{\sqrt{2}{r}_e\pi }{r_{c}4}-\ln (\frac{r_s{r}_c}{(4\pi r_e{)}^2})-\frac{r_c}{\sqrt{2}{r}_e}$

using $t_c={\int }_0^c\sqrt{1^2-(\frac{v(t)}{c}{)}^2}\partial t=\frac{\pi }{4}{t}_e$

on $0=\frac{\sqrt{2}{t}_c{r}_e}{r_c{t}_e}-\ln (\frac{r_s{r}_c}{(4\pi r_e{)}^2})-\frac{r_c}{\sqrt{2}{r}_e}$

using ${\int }_{\partial r}^{r_e}\frac{q^{\prime }(r)}{q(r)}={\int }_{\partial q}^{q(r_e)}\frac{1}{q}=\ln (q(r_e))$

on $0={\int }^{r_e}\frac{\sqrt{2}{t}_c}{r_c{t}_e}\partial r-\frac{\frac{-\frac{2r_s}{r}{r}_c}{(4\pi r{)}^2}}{\frac{r_s{r}_c}{(4\pi r{)}^2}}\partial r+\frac{r_c}{\sqrt{2}{r}^2}\partial r$

using $\frac{\partial r^2}{\partial s^2}=\frac{\partial r}{\partial s^2}\partial r=\int \frac{4\pi \frac{r_c}{\sqrt{2}}}{4\pi r^2}\partial r=\frac{-r_c}{\sqrt{2}r}$

on $0={\int }^{r_e}-\frac{\tau \partial s^2}{r\partial r^2}\partial r-\frac{\frac{-\frac{2r_s}{r}{r}_c}{(4\pi r{)}^2}}{\frac{r_s{r}_c}{(4\pi r{)}^2}}\partial r-\frac{\partial r^2}{\partial s^2}{r}^{-2}\partial r$

using $\frac{\partial {\tau }^2}{\partial t^2}=1-\frac{r_s}{r}=-\frac{\partial r^2}{\partial s^2}$

on $0=\partial r{\int }^{r_e}\frac{\tau \partial t^2}{r\partial {\tau }^2}\partial r-\frac{\frac{-\frac{2r_s}{r}{r}_c}{(4\pi r{)}^2}}{\frac{r_s{r}_c}{(4\pi r{)}^2}}-\frac{\partial r^2}{\partial s^2}{r}^{-2}$

using $...$

on $0={\int }^{r_e}\frac{\partial t^2-\partial s^2-\partial r^2}{\partial s^2}\partial r$

using $(\varphi ,\theta ):=(0,0)$

on $d{s}^2=((\genfrac{}{}{0ex}{}{R}{d\mathrm{\Omega }})\mapsto (\genfrac{}{}{0ex}{}{\sqrt[3]{r^3+r_s^3}}{d{\theta }^2+{\sin }^2\theta d{\varphi }^2}))(\frac{d{t}^2}{\frac{R}{R-r_s}}-\frac{d{R}^2}{\frac{R-r_s}{R}}-R^{2}d\mathrm{\Omega })$