PlanetPhysics/Riccati Equation 2

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The nonlinear [[../DifferentialEquations/|differential equation]]

dydx=f(x)+g(x)y+h(x)y2

is called the Riccati equation .\, If\, h(x)0,\, it becomes a linear differential equation; if\, f(x)0,\, then it becomes a Bernoulli equation.\, There is no general method for integrating explicitely the equation (1), but via the substitution y:=w(x)h(x)w(x) one can convert it to a second order homogeneous linear differential equation with non-constant coefficients.\\

If one can find a particular solution \,y0(x),\, then one can easily verify that the substitution

y:=y0(x)+1w(x)

converts (1) to

dwdx+[g(x)+2h(x)y0(x)]w+h(x)=0,

which is a linear differential equation of first order with respect to the [[../Bijective/|function]] \,w=w(x).\\

Example. \, The Riccati equation

dyx=3+3x2yxy2

has the particular solution\, y:=3x.\, Solve the equation.

We substitute\, y:=3x+1w(x)\, to (4), getting dwdx3x2wx=0. For solving this first order equation we can put\, w=uv,\, w=uv+uv,\, writing the equation as

u(v3x3v)+uv=x,

where we choose the value of the expression in parentheses equal to 0: dvdx3x2v=0 After separation of variables and integrating, we obtain from here a solution\, v=ex3,\, which is set to the equation (5): dudxex3=x Separating the variables yields du=xex3dx and integrating: u=C+xex3dx. Thus we have w=w(x)=uv=ex3[C+xex3dx], whence the general solution of the Riccati equation (4) is Failed to parse (syntax error): {\displaystyle y \,:=\, 3x+\frac{e^{-x^3}}{C+\int xe^{-x^3}\,dx}.\\}

It can be proved that if one knows three different solutions of Riccati equation (1), then any other solution may be expressed as a rational function of the three known solutions.

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