University of Florida/Egm6321/F10.TEAM1.WILKS/Mtg21

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EGM6321 - Principles of Engineering Analysis 1, Fall 2009

Mtg 21: Thurs, 8Oct09


P.20-4 (continued)

ax1  is a homgenous solution a 

u1(x)=c1x1 

2) b=2ax2  is another homogeneous solution since b2b2=0 

u2(x)=c2x2 

(Verify u1  and u2  are linearly independant components of W 

3) b=6,a=14  left hand side of Eq(1) p20-4 =7x4  , where =7x4  is the 1st term on the right hand side

for b=6,a=1414x6 

4) b=5,a=16  left hand side of Eq(1) p20-4 =3x3  , where =3x3  is the 2nd term on the right hand side

for b=5,a=1616x5 

Llinearity of ordinary differential equation   superposition

yP(x)=14x6+16x5 

y(x)=c1x1+c2x2+yP(x)  , where c1x1+c2x2=yH(x) 

Alternative method to obtain full solution for non-homogeneous L2_ODE_VC knowing only one homogeneous solution (e.g. obtained by trial solution) (bypassing reduction of order method2-undertermined factor for u2  and variation of parameter method)

Eq.(1) P.3-1 = y+a1(x)y+a0(x)y=f(x) 

Assume having found u1(x) , a homogeneous solution: u1+a1(x)u1+a0(x)u1=0 

Consider: y(x)=U(x)u1(x)  , where U(x)  is an undetermined factor



Follow the same argument as on P.17-2 to obtain:

f(x)=U(a1u1+2u1)+Uu1

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NOTE: this equation is missing the dependant variable U  in front of U  term due to reduction of order method ϕ  

Z(x):=U(x)

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u1(x)Z+[a1(x)u1(x)+2u1(x)]Z=f(x)

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where u1(x)  and [a1(x)u1(x)+2u1(x)]  are known

Non-homogeneous L1_ODE_VC solution for Z(x)  : Eq.(4) P.8-2

U(x)=xZ(s)ds

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y(x)=U(x)u1(x)

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ref: K p.28, problem 1.1ab

a) u1(x)=ex  , (x1)yxy+y=0 

Trial solution y(x)=erx  , where r=  constant

Find r1,r2 

How many valid homogeneous solutions to u1=er1x , find u2  using undetermined factor method


References


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